Lady Gaga calls vomit-based SXSW performance 'art in its purest form'

London artist Millie Brown vomited paint over the 'Artpop' star during Austin live show

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Lady Gaga has defended her recent SXSW performance, where she was vomited on by a performance artist, saying it was "art in its purest form."

London artist Millie Brown vomited paint over the 'Artpop' star, covering Gaga in luminous green liquid as she played 'Swine' at the US festival. Brown then mounted a bucking bronco in the shape of a pig alongside Gaga and simulating sex with the singer until the song's completion.

CNN reports that during Gaga's appearance on NBC's Today show yesterday (March 21), she claimed that her and Brown's stage show displayed the essence of her 'Artpop' album, adding that neither performer was surprised by the negative reaction they received from some quarters.

"I guess we weren't completely surprised. [Millie Brown] and I know that not everybody's going to love that performance," Gaga said of the backlash. "But we both really believe in artistic expression and strong identities. I support her and what she does. 'Artpop', my new album, is about bringing art and music together and the spirit of creative rebellion. For us, that performance was art in its purest form. But we totally understand that some people won't be into it."

Brown previously responded to claims from pop star Demi Lovato that the performance glamourised eating disorders, saying, "There's a clear difference between using my body to create something beautiful, to express myself and feel powerful, rather than using it to punish myself and conform to society's standards."



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